What is (x-3)^2+(y-5)^2-54=0 ?

The solution to (x-3)^2+(y-5)^2-54=0 is Circle with (a,b)=(3,5),r=sqrt(54)

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(x-3)^2+(y-5)^2-54=0

(x - 3)^{2} + (y - 5)^{2} - 54 = 0

(a, b) = (3, 5), r = 54

Solution steps

(x - 3)^{2} + (y - 5)^{2} - 54 = 0

Rewrite

(x - 3)^{2} + (y - 5)^{2} - 54 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = (54)^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 54

What is (x-3)^2+(y-5)^2-54=0 ?
The solution to (x-3)^2+(y-5)^2-54=0 is Circle with (a,b)=(3,5),r=sqrt(54)