What is (x+4)^2+(y+1)^2=sqrt(30) ?

The solution to (x+4)^2+(y+1)^2=sqrt(30) is Circle with (a,b)=(-4,-1),r=sqrt(\sqrt{30)}

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(x+4)^2+(y+1)^2=sqrt(30)

(x + 4)^{2} + (y + 1)^{2} = 30

(a, b) = (- 4, - 1), r = 30

Solution steps

(x + 4)^{2} + (y + 1)^{2} = 30

Rewrite

(x + 4)^{2} + (y + 1)^{2} = 30

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 1))^{2} = (30)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 1), r = 30

x^{2} + y^{2} + 6 x - 8 y = - 24

y^{2} = 1 - 1 x^{2}

(x + 1)^{2} + (y + \frac{15}{8})^{2} = 5

x^{2} + y^{2} + 6 x + 4 = 3

(x + 5)^{2} + (y - 7)^{2} = 48

What is (x+4)^2+(y+1)^2=sqrt(30) ?
The solution to (x+4)^2+(y+1)^2=sqrt(30) is Circle with (a,b)=(-4,-1),r=sqrt(\sqrt{30)}