What is 25x^2+25y^2+60y-20x-360=0 ?

The solution to 25x^2+25y^2+60y-20x-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4

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25x^2+25y^2+60y-20x-360=0

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

Solution steps

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

Rewrite

25 x^{2} + 25 y^{2} + 60 y - 20 x - 360 = 0

in the form of the standard circle equation

(x - \frac{2}{5})^{2} + (y - (- \frac{6}{5}))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{2}{5}, - \frac{6}{5}), r = 4

What is 25x^2+25y^2+60y-20x-360=0 ?
The solution to 25x^2+25y^2+60y-20x-360=0 is Circle with (a,b)=(2/5 ,-6/5),r=4