What is 3x^2+3y^2=6 ?

The solution to 3x^2+3y^2=6 is Circle with (a,b)=(0,0),r=sqrt(2)

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3x^2+3y^2=6

3 x^{2} + 3 y^{2} = 6

(a, b) = (0, 0), r = 2

Solution steps

3 x^{2} + 3 y^{2} = 6

Rewrite

3 x^{2} + 3 y^{2} = 6

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + (y - 3)^{2} - 49 = 0

2 x^{2} + 2 y^{2} - 6 x - 14 y - 3 = 0

4 x^{2} + 4 y^{2} - 16 x + 12 y + 21 = 0

(x + 2)^{2} + (y + 2)^{2} = 3

(x + (- 3))^{2} + (y - 2)^{2} = 16

What is 3x^2+3y^2=6 ?
The solution to 3x^2+3y^2=6 is Circle with (a,b)=(0,0),r=sqrt(2)