What is x^2+y^2-2x>= 0 ?

The solution to x^2+y^2-2x>= 0 is Circle with (a,b)=(1,0),r=1

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x^2+y^2-2x>= 0

x^{2} + y^{2} - 2 x \geq 0

(a, b) = (1, 0), r = 1

Solution steps

x^{2} + y^{2} - 2 x \geq 0

Rewrite

x^{2} + y^{2} - 2 x \geq 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 1

What is x^2+y^2-2x>= 0 ?
The solution to x^2+y^2-2x>= 0 is Circle with (a,b)=(1,0),r=1