What is (x)^2+(y)^2=169 ?

The solution to (x)^2+(y)^2=169 is Circle with (a,b)=(0,0),r=13

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(x)^2+(y)^2=169

(x)^{2} + (y)^{2} = 169

(a, b) = (0, 0), r = 13

Solution steps

x^{2} + y^{2} = 169

Rewrite

x^{2} + y^{2} = 169

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 13

x^{2} + y^{2} + 10 x + 16 y - 107 = 0

(x - 5)^{2} + (y - 3)^{2} = 16

(x - 1)^{2} + y^{2} = 6

2 x - 4 y - x^{2} - y^{2} - 1 \geq 0

(x - (- 15))^{2} + (y - 37)^{2} = 2^{2}

What is (x)^2+(y)^2=169 ?
The solution to (x)^2+(y)^2=169 is Circle with (a,b)=(0,0),r=13