What is (x+1)^2+(y-5)^2=9 ?

The solution to (x+1)^2+(y-5)^2=9 is Circle with (a,b)=(-1,5),r=3

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(x+1)^2+(y-5)^2=9

(x + 1)^{2} + (y - 5)^{2} = 9

(a, b) = (- 1, 5), r = 3

Solution steps

(x + 1)^{2} + (y - 5)^{2} = 9

Rewrite

(x + 1)^{2} + (y - 5)^{2} = 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, 5), r = 3

What is (x+1)^2+(y-5)^2=9 ?
The solution to (x+1)^2+(y-5)^2=9 is Circle with (a,b)=(-1,5),r=3