What is (x-5)^{(2)}+(y+10)^{(2)}=5^{(2)} ?

The solution to (x-5)^{(2)}+(y+10)^{(2)}=5^{(2)} is Circle with (a,b)=(5,-10),r=5

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(x-5)^{(2)}+(y+10)^{(2)}=5^{(2)}

(x - 5)^{(2)} + (y + 10)^{(2)} = 5^{(2)}

(a, b) = (5, - 10), r = 5

Solution steps

(x - 5)^{2} + (y + 10)^{2} = 5^{2}

Rewrite

(x - 5)^{2} + (y + 10)^{2} = 5^{2}

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 10))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, - 10), r = 5

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

(x - 1)^{2} + (y - 3)^{2} = 64

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

(x - 7)^{(2)} + (y + 15)^{(2)} = 200

x^{2} + (y - 3)^{2} = 2.6

What is (x-5)^{(2)}+(y+10)^{(2)}=5^{(2)} ?
The solution to (x-5)^{(2)}+(y+10)^{(2)}=5^{(2)} is Circle with (a,b)=(5,-10),r=5