What is (x-4)^2+(y-(-3))^2=5^2 ?

The solution to (x-4)^2+(y-(-3))^2=5^2 is Circle with (a,b)=(4,-3),r=5

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(x-4)^2+(y-(-3))^2=5^2

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

(a, b) = (4, - 3), r = 5

Solution steps

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

Rewrite

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 3), r = 5

(x - 1)^{2} + (y - 3)^{2} = 64

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

(x - 7)^{(2)} + (y + 15)^{(2)} = 200

x^{2} + (y - 3)^{2} = 2.6

16 x^{2} + 96 x + 16 y^{2} - 14 y = 315

What is (x-4)^2+(y-(-3))^2=5^2 ?
The solution to (x-4)^2+(y-(-3))^2=5^2 is Circle with (a,b)=(4,-3),r=5