What is 4x^2+4y^2-10x-12y=20 ?

The solution to 4x^2+4y^2-10x-12y=20 is Circle with (a,b)=(5/4 , 3/2),r=(sqrt(141))/4

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4x^2+4y^2-10x-12y=20

4 x^{2} + 4 y^{2} - 10 x - 12 y = 20

(a, b) = (\frac{5}{4}, \frac{3}{2}), r = \frac{141}{4}

Solution steps

4 x^{2} + 4 y^{2} - 10 x - 12 y = 20

Rewrite

4 x^{2} + 4 y^{2} - 10 x - 12 y = 20

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - \frac{3}{2})^{2} = (\frac{141}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, \frac{3}{2}), r = \frac{141}{4}

What is 4x^2+4y^2-10x-12y=20 ?
The solution to 4x^2+4y^2-10x-12y=20 is Circle with (a,b)=(5/4 , 3/2),r=(sqrt(141))/4