What is 2x^2+2y^2+13x-9y-20=0 ?

The solution to 2x^2+2y^2+13x-9y-20=0 is Circle with (a,b)=(-13/4 , 9/4),r=(sqrt(205))/(2sqrt(2))

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2x^2+2y^2+13x-9y-20=0

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

(a, b) = (- \frac{13}{4}, \frac{9}{4}), r = \frac{205}{2 2}

Solution steps

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

Rewrite

2 x^{2} + 2 y^{2} + 13 x - 9 y - 20 = 0

in the form of the standard circle equation

(x - (- \frac{13}{4}))^{2} + (y - \frac{9}{4})^{2} = (\frac{205}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{13}{4}, \frac{9}{4}), r = \frac{205}{2 2}

5 x^{2} + 5 y^{2} = 245

(x - 0.5)^{2} + (y - 1)^{2} = (\frac{1}{2})^{2}

x^{2} + y^{2} + 6 x + 14 y + 37 = 0

(x - 3)^{2} + (- y + 2)^{2} = 2^{2}

x^{2} + y^{2} + 10 x + 18 y + 42 = 0

What is 2x^2+2y^2+13x-9y-20=0 ?
The solution to 2x^2+2y^2+13x-9y-20=0 is Circle with (a,b)=(-13/4 , 9/4),r=(sqrt(205))/(2sqrt(2))