What is x^2+y^2+6y-7=0 ?

The solution to x^2+y^2+6y-7=0 is Circle with (a,b)=(0,-3),r=4

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x^2+y^2+6y-7=0

x^{2} + y^{2} + 6 y - 7 = 0

(a, b) = (0, - 3), r = 4

Solution steps

x^{2} + y^{2} + 6 y - 7 = 0

Rewrite

x^{2} + y^{2} + 6 y - 7 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, - 3), r = 4

What is x^2+y^2+6y-7=0 ?
The solution to x^2+y^2+6y-7=0 is Circle with (a,b)=(0,-3),r=4