What is x^2+(y-4)^2=36 ?

The solution to x^2+(y-4)^2=36 is Circle with (a,b)=(0,4),r=6

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x^2+(y-4)^2=36

x^{2} + (y - 4)^{2} = 36

(a, b) = (0, 4), r = 6

Solution steps

x^{2} + (y - 4)^{2} = 36

Rewrite

x^{2} + (y - 4)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 6

What is x^2+(y-4)^2=36 ?
The solution to x^2+(y-4)^2=36 is Circle with (a,b)=(0,4),r=6