What is 3x^2+3y^2-18-12y=108 ?

The solution to 3x^2+3y^2-18-12y=108 is Circle with (a,b)=(0,2),r=sqrt(46)

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3x^2+3y^2-18-12y=108

3 x^{2} + 3 y^{2} - 18 - 12 y = 108

(a, b) = (0, 2), r = 46

Solution steps

3 x^{2} + 3 y^{2} - 18 - 12 y = 108

Rewrite

3 x^{2} + 3 y^{2} - 18 - 12 y = 108

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = (46)^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 46

What is 3x^2+3y^2-18-12y=108 ?
The solution to 3x^2+3y^2-18-12y=108 is Circle with (a,b)=(0,2),r=sqrt(46)