What is the foci (x^2}{81}+\frac{y^2)/9 =1 ?

The foci (x^2}{81}+\frac{y^2)/9 =1 is (6sqrt(2),0),(-6sqrt(2),0)

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foci (x^2}{81}+\frac{y^2)/9 =1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{9} = 1

(62, 0), (- 62, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 3^{2} : 62

(0 + 62, 0), (0 - 62, 0)

Refine

(62, 0), (- 62, 0)

16 x^{2} + 16 y^{2} + 32 x + 8 y = 47

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

y^{2} = - 16 x

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

x = - \frac{1}{8} y^{2}

What is the foci (x^2}{81}+\frac{y^2)/9 =1 ?
The foci (x^2}{81}+\frac{y^2)/9 =1 is (6sqrt(2),0),(-6sqrt(2),0)