What is the directrix y^2=-16x ?

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directrix y^2=-16x

directrix

y^{2} = - 16 x

x = 4

Solution steps

Rewrite

y^{2} = - 16 x

in the standard form:

4 (- 4) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 4)

Refine

x = 4

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1

x = - \frac{1}{8} y^{2}

x^{2} + y^{2} = 13

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

- 1 = x^{2} - y^{2}