What is (x+1)^2+(y+3)^2=44.1 ?

The solution to (x+1)^2+(y+3)^2=44.1 is Circle with (a,b)=(-1,-3),r=6.64078…

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(x+1)^2+(y+3)^2=44.1

(x + 1)^{2} + (y + 3)^{2} = 44.1

(a, b) = (- 1, - 3), r = 6.64078 \dots

Solution steps

(x + 1)^{2} + (y + 3)^{2} = 44.1

Rewrite

(x + 1)^{2} + (y + 3)^{2} = 44.1

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 3))^{2} = 6.64078 \dots^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 3), r = 6.64078 \dots

What is (x+1)^2+(y+3)^2=44.1 ?
The solution to (x+1)^2+(y+3)^2=44.1 is Circle with (a,b)=(-1,-3),r=6.64078…