What is (x+4)^2+(y+1/3)^2=4^2 ?

The solution to (x+4)^2+(y+1/3)^2=4^2 is Circle with (a,b)=(-4,-1/3),r=4

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(x+4)^2+(y+1/3)^2=4^2

(x + 4)^{2} + (y + \frac{1}{3})^{2} = 4^{2}

(a, b) = (- 4, - \frac{1}{3}), r = 4

Solution steps

(x + 4)^{2} + (y + \frac{1}{3})^{2} = 4^{2}

Rewrite

(x + 4)^{2} + (y + \frac{1}{3})^{2} = 4^{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- \frac{1}{3}))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, - \frac{1}{3}), r = 4

(x + 2)^{2} + (y + 5)^{2} = 104

x^{2} + y^{2} + y = 16

4 y^{2} + 4 x^{2} - 24 x + 36 y = - 81

x^{2} + y^{2} - 8 x + 4 y + 11 \leq 0

x^{2} + y^{2} - 20 x + 36 y + 353 = 0

What is (x+4)^2+(y+1/3)^2=4^2 ?
The solution to (x+4)^2+(y+1/3)^2=4^2 is Circle with (a,b)=(-4,-1/3),r=4