What is y=2x^2+6x+4+67y ?

The solution to y=2x^2+6x+4+67y is Parabola with (h,k)=(-3/2 , 1/132),p=-33/4

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y=2x^2+6x+4+67y

y = 2 x^{2} + 6 x + 4 + 67 y

(h, k) = (- \frac{3}{2}, \frac{1}{132}), p = - \frac{33}{4}

Solution steps

y = 2 x^{2} + 6 x + 4 + 67 y

Rewrite

y = 2 x^{2} + 6 x + 4 + 67 y

in the standard form

4 (- \frac{33}{4}) (y - \frac{1}{132}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{1}{132}), p = - \frac{33}{4}

y^{2} + 8 x = 0

\frac{x ^{2}}{25} - \frac{y}{16} = 1

2 x^{2} - 4 y + 8 = 0

2 y^{2} + 12 y - x + 2 = 0

y^{2} - x = 0

What is y=2x^2+6x+4+67y ?
The solution to y=2x^2+6x+4+67y is Parabola with (h,k)=(-3/2 , 1/132),p=-33/4