What is (x^2)/(25)-y/(16)=1 ?

The solution to (x^2)/(25)-y/(16)=1 is Parabola with (h,k)=(0,-16),p= 25/64

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(x^2)/(25)-y/(16)=1

\frac{x ^{2}}{25} - \frac{y}{16} = 1

(h, k) = (0, - 16), p = \frac{25}{64}

Solution steps

\frac{x ^{2}}{25} - \frac{y}{16} = 1

Rewrite

\frac{x ^{2}}{25} - \frac{y}{16} = 1

in the standard form:

4 \cdot \frac{25}{64} (y - (- 16)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 16), p = \frac{25}{64}

2 x^{2} - 4 y + 8 = 0

2 y^{2} + 12 y - x + 2 = 0

y^{2} - x = 0

(y - 3)^{2} = 2 (x + 1)

x^{2} + y - 4 = 0

What is (x^2)/(25)-y/(16)=1 ?
The solution to (x^2)/(25)-y/(16)=1 is Parabola with (h,k)=(0,-16),p= 25/64