What is 36y^2+72x-132y-239=0 ?

The solution to 36y^2+72x-132y-239=0 is Parabola with (h,k)=(5, 11/6),p=-1/2

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36y^2+72x-132y-239=0

36 y^{2} + 72 x - 132 y - 239 = 0

(h, k) = (5, \frac{11}{6}), p = - \frac{1}{2}

Solution steps

36 y^{2} + 72 x - 132 y - 239 = 0

Rewrite

36 y^{2} + 72 x - 132 y - 239 = 0

in the standard form

4 (- \frac{1}{2}) (x - 5) = (y - \frac{11}{6})^{2}

Therefore parabola properties are:

(h, k) = (5, \frac{11}{6}), p = - \frac{1}{2}

x^{2} - 6 y = 0

4 y^{2} + 18 = 96 x

y - x^{2} = 1

y = 2 x^{2} + 6 x + 4 + 67 y

y^{2} + 8 x = 0

What is 36y^2+72x-132y-239=0 ?
The solution to 36y^2+72x-132y-239=0 is Parabola with (h,k)=(5, 11/6),p=-1/2