What is (x^2}{16}-\frac{y^2)/4 =1 ?

The solution to (x^2}{16}-\frac{y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=4,b=2

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(x^2}{16}-\frac{y^2)/4 =1

\frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 4, b = 2

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

y^{2} = 8 x

y^{2} = - 8 x

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

x^{2} + 4 y^{2} = 16

What is (x^2}{16}-\frac{y^2)/4 =1 ?
The solution to (x^2}{16}-\frac{y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=4,b=2