What is the foci (y^2)/(64)-(x^2)/(36)=1 ?

The foci (y^2)/(64)-(x^2)/(36)=1 is (0,10),(0,-10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

foci (y^2)/(64)-(x^2)/(36)=1

foci

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} + 6^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

x^{2} + 4 y^{2} = 16

4 x^{2} + 3 y^{2} + 8 x - 24 y + 51 = 0

9 y^{2} - 25 x^{2} = 225

x^{2} - y^{2} = 4

What is the foci (y^2)/(64)-(x^2)/(36)=1 ?
The foci (y^2)/(64)-(x^2)/(36)=1 is (0,10),(0,-10)