What is (x-8)^2+y^2=7 ?

The solution to (x-8)^2+y^2=7 is Circle with (a,b)=(8,0),r=sqrt(7)

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(x-8)^2+y^2=7

(x - 8)^{2} + y^{2} = 7

(a, b) = (8, 0), r = 7

Solution steps

(x - 8)^{2} + y^{2} = 7

Rewrite

(x - 8)^{2} + y^{2} = 7

in the form of the standard circle equation

(x - 8)^{2} + (y - 0)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (8, 0), r = 7

(x - 2)^{2} + (y - 2)^{2} = 2^{2}

(x - 1)^{2} + (y - 4)^{2} = 16

x^{2} + 2 x + 10 + y^{2} - 6 y - 10 = 0

x^{2} = 8 - y^{2}

x^{2} + y^{2} - 4 x - 10 y + 20 = 0

What is (x-8)^2+y^2=7 ?
The solution to (x-8)^2+y^2=7 is Circle with (a,b)=(8,0),r=sqrt(7)