What is x^2+y^2-4x-10y+20=0 ?

The solution to x^2+y^2-4x-10y+20=0 is Circle with (a,b)=(2,5),r=3

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x^2+y^2-4x-10y+20=0

x^{2} + y^{2} - 4 x - 10 y + 20 = 0

(a, b) = (2, 5), r = 3

Solution steps

x^{2} + y^{2} - 4 x - 10 y + 20 = 0

Rewrite

x^{2} + y^{2} - 4 x - 10 y + 20 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 5), r = 3

3 x^{2} + 3 y^{2} + 6 x - 8 y = 48

x^{2} + y^{2} - 6 x - 10 y + 33 = 0

(x - 1)^{2} + (y - 4)^{2} - 9 = 0

X^{2} + Y^{2} = 25

x^{2} + y^{2} - 6 x + 8 y + 16 = 0

What is x^2+y^2-4x-10y+20=0 ?
The solution to x^2+y^2-4x-10y+20=0 is Circle with (a,b)=(2,5),r=3