What is x^2+y^2+4x+6y-23=0 ?

The solution to x^2+y^2+4x+6y-23=0 is Circle with (a,b)=(-2,-3),r=6

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x^2+y^2+4x+6y-23=0

x^{2} + y^{2} + 4 x + 6 y - 23 = 0

(a, b) = (- 2, - 3), r = 6

Solution steps

x^{2} + y^{2} + 4 x + 6 y - 23 = 0

Rewrite

x^{2} + y^{2} + 4 x + 6 y - 23 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 6

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{16} = 1

(x - 2)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} + 12 x - 10 y = 12

x^{2} + 4 x + y^{2} - 2 y + 1 = 0

x^{2} - 2 x + y^{2} + 4 y + 1 = 0

What is x^2+y^2+4x+6y-23=0 ?
The solution to x^2+y^2+4x+6y-23=0 is Circle with (a,b)=(-2,-3),r=6