What is 4x^{(2)}+4y^{(2)}+24x-8y-9=0 ?

The solution to 4x^{(2)}+4y^{(2)}+24x-8y-9=0 is Circle with (a,b)=(-3,1),r= 7/2

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4x^{(2)}+4y^{(2)}+24x-8y-9=0

4 x^{(2)} + 4 y^{(2)} + 24 x - 8 y - 9 = 0

(a, b) = (- 3, 1), r = \frac{7}{2}

Solution steps

4 x^{2} + 4 y^{2} + 24 x - 8 y - 9 = 0

Rewrite

4 x^{2} + 4 y^{2} + 24 x - 8 y - 9 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = \frac{7}{2}

x^{2} + 4 x + y^{2} - 6 y + 9 = 0

(x - 5)^{2} + (y - 6)^{2} = 36

x^{2} + y^{2} + 8 x - 18 y - 47 = 0

x^{2} + y^{2} - 4 x - 2 y = 0

(x + 6)^{2} + y^{2} = 36

What is 4x^{(2)}+4y^{(2)}+24x-8y-9=0 ?
The solution to 4x^{(2)}+4y^{(2)}+24x-8y-9=0 is Circle with (a,b)=(-3,1),r= 7/2