What is 4x^2+4y^2-12x+24y+9=0 ?

The solution to 4x^2+4y^2-12x+24y+9=0 is Circle with (a,b)=(3/2 ,-3),r=3

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4x^2+4y^2-12x+24y+9=0

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

(a, b) = (\frac{3}{2}, - 3), r = 3

Solution steps

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

Rewrite

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 3), r = 3

(x + 1)^{2} + y^{2} = 25

x^{2} + y^{2} - 4 x + 8 y + 4 = 0

(x - 1)^{2} + (y + 3)^{2} = 16

x^{2} + (y - 2)^{2} = 9

x^{2} + y^{2} - 6 x - 4 y = 36

What is 4x^2+4y^2-12x+24y+9=0 ?
The solution to 4x^2+4y^2-12x+24y+9=0 is Circle with (a,b)=(3/2 ,-3),r=3