What is (x-1)^2+(y+3)^2=16 ?

The solution to (x-1)^2+(y+3)^2=16 is Circle with (a,b)=(1,-3),r=4

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(x-1)^2+(y+3)^2=16

(x - 1)^{2} + (y + 3)^{2} = 16

(a, b) = (1, - 3), r = 4

Solution steps

(x - 1)^{2} + (y + 3)^{2} = 16

Rewrite

(x - 1)^{2} + (y + 3)^{2} = 16

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 4

x^{2} + (y - 2)^{2} = 9

x^{2} + y^{2} - 6 x - 4 y = 36

x^{2} + y^{2} - 4 y + 1 = 0

x^{2} + y^{2} + 6 x - 4 y + 12 = 0

x^{2} + y^{2} = 1 0^{2}

What is (x-1)^2+(y+3)^2=16 ?
The solution to (x-1)^2+(y+3)^2=16 is Circle with (a,b)=(1,-3),r=4