What is (x+13)^2+(y+11)^2=56 ?

The solution to (x+13)^2+(y+11)^2=56 is Circle with (a,b)=(-13,-11),r=sqrt(56)

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(x+13)^2+(y+11)^2=56

(x + 13)^{2} + (y + 11)^{2} = 56

(a, b) = (- 13, - 11), r = 56

Solution steps

(x + 13)^{2} + (y + 11)^{2} = 56

Rewrite

(x + 13)^{2} + (y + 11)^{2} = 56

in the form of the standard circle equation

(x - (- 13))^{2} + (y - (- 11))^{2} = (56)^{2}

Therefore the circle properties are:

(a, b) = (- 13, - 11), r = 56

x^{2} + y^{2} + 14 x - 16 y = 87

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- 2 x^{2} - 36 x - 2 y^{2} - 112 = 0

x^{2} + y^{2} + 4 x + 12 y + 36 = 36

x^{2} + y^{2} + 8 x - 10 y + 1 = 0

What is (x+13)^2+(y+11)^2=56 ?
The solution to (x+13)^2+(y+11)^2=56 is Circle with (a,b)=(-13,-11),r=sqrt(56)