What is -2x^2-36x-2y^2-112=0 ?

The solution to -2x^2-36x-2y^2-112=0 is Circle with (a,b)=(-9,0),r=5

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-2x^2-36x-2y^2-112=0

- 2 x^{2} - 36 x - 2 y^{2} - 112 = 0

(a, b) = (- 9, 0), r = 5

Solution steps

- 2 x^{2} - 36 x - 2 y^{2} - 112 = 0

Rewrite

- 2 x^{2} - 36 x - 2 y^{2} - 112 = 0

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 9, 0), r = 5

x^{2} + y^{2} + 4 x + 12 y + 36 = 36

x^{2} + y^{2} + 8 x - 10 y + 1 = 0

x^{2} + y^{2} - 6 x - 10 y + 18 = 0

x^{2} + y^{2} + 6 x + 5 y = - \frac{45}{4}

x^{2} + y^{2} + 2 x - 10 y - 10 = 0

What is -2x^2-36x-2y^2-112=0 ?
The solution to -2x^2-36x-2y^2-112=0 is Circle with (a,b)=(-9,0),r=5