What is (x-10)^2+y^2= 1/4 ?

The solution to (x-10)^2+y^2= 1/4 is Circle with (a,b)=(10,0),r= 1/2

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(x-10)^2+y^2= 1/4

(x - 10)^{2} + y^{2} = \frac{1}{4}

(a, b) = (10, 0), r = \frac{1}{2}

Solution steps

(x - 10)^{2} + y^{2} = \frac{1}{4}

Rewrite

(x - 10)^{2} + y^{2} = \frac{1}{4}

in the form of the standard circle equation

(x - 10)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (10, 0), r = \frac{1}{2}

5 x^{2} + 5 y^{2} + 10 x - y = 0

(x + 13)^{2} + (y + 11)^{2} = 56

x^{2} + y^{2} + 14 x - 16 y = 87

x^{2} + y^{2} - 8 x - 6 y + 21 = 0

- 2 x^{2} - 36 x - 2 y^{2} - 112 = 0

What is (x-10)^2+y^2= 1/4 ?
The solution to (x-10)^2+y^2= 1/4 is Circle with (a,b)=(10,0),r= 1/2