What is x^2+y^2-8x-20y+115=0 ?

The solution to x^2+y^2-8x-20y+115=0 is Circle with (a,b)=(4,10),r=1

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x^2+y^2-8x-20y+115=0

x^{2} + y^{2} - 8 x - 20 y + 115 = 0

(a, b) = (4, 10), r = 1

Solution steps

x^{2} + y^{2} - 8 x - 20 y + 115 = 0

Rewrite

x^{2} + y^{2} - 8 x - 20 y + 115 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 10)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (4, 10), r = 1

x^{2} + y^{2} - 6 x + 2 y = 6

(x + 1)^{2} + y^{2} = 10

(x - 10)^{2} + y^{2} = \frac{1}{4}

5 x^{2} + 5 y^{2} + 10 x - y = 0

(x + 13)^{2} + (y + 11)^{2} = 56

What is x^2+y^2-8x-20y+115=0 ?
The solution to x^2+y^2-8x-20y+115=0 is Circle with (a,b)=(4,10),r=1