What is 4x^2+4y^2=64 ?

The solution to 4x^2+4y^2=64 is Circle with (a,b)=(0,0),r=4

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4x^2+4y^2=64

4 x^{2} + 4 y^{2} = 64

(a, b) = (0, 0), r = 4

Solution steps

4 x^{2} + 4 y^{2} = 64

Rewrite

4 x^{2} + 4 y^{2} = 64

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

(x - 1)^{2} + (y + 5)^{2} = 9

16 x^{2} + 16 y^{2} - 16 x + 24 y - 3 = 0

2 x^{2} + 2 y^{2} + 5 x + 3 y + 2 = 0

(y + 4)^{2} + (x + 3)^{2} = 25

16 x^{2} + 96 x + 16 y^{2} - 40 y = 315

What is 4x^2+4y^2=64 ?
The solution to 4x^2+4y^2=64 is Circle with (a,b)=(0,0),r=4