What is (y+4)^2+(x+3)^2=25 ?

The solution to (y+4)^2+(x+3)^2=25 is Circle with (a,b)=(-3,-4),r=5

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(y+4)^2+(x+3)^2=25

(y + 4)^{2} + (x + 3)^{2} = 25

(a, b) = (- 3, - 4), r = 5

Solution steps

(y + 4)^{2} + (x + 3)^{2} = 25

Rewrite

(y + 4)^{2} + (x + 3)^{2} = 25

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 4), r = 5

16 x^{2} + 96 x + 16 y^{2} - 40 y = 315

x^{2} - 4 x + y^{2} + 8 y = - 4

x^{2} + y^{2} + 4 y - 1 = 0

x^{2} + y^{2} + 4 x - 8 y + 9 = 0

x^{2} + y^{2} < 25

What is (y+4)^2+(x+3)^2=25 ?
The solution to (y+4)^2+(x+3)^2=25 is Circle with (a,b)=(-3,-4),r=5