What is x^2+14x+y^2-6y-23=0 ?

The solution to x^2+14x+y^2-6y-23=0 is Circle with (a,b)=(-7,3),r=9

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x^2+14x+y^2-6y-23=0

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

(a, b) = (- 7, 3), r = 9

Solution steps

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

Rewrite

x^{2} + 14 x + y^{2} - 6 y - 23 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 3)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 7, 3), r = 9

x = 2 y - y^{2}

x^{2} - 2 x + y^{2} + 4 y = 4

x = 2 y^{2}

f (x) = - x^{2}

- \frac{1}{20} x^{2}

What is x^2+14x+y^2-6y-23=0 ?
The solution to x^2+14x+y^2-6y-23=0 is Circle with (a,b)=(-7,3),r=9