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Popular >

foci x=2y^2

Solution

foci

x = 2 y^{2}

Solution

(\frac{1}{8}, 0)

Solution steps

Rewrite

x = 2 y^{2}

in the standard form:

4 \cdot \frac{1}{8} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{8}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + \frac{1}{8}, 0)

Refine

(\frac{1}{8}, 0)

Popular Examples

vertices f(x)=-x^2 vertices

f (x) = - x^{2}

foci-1/20 x^2 foci

- \frac{1}{20} x^{2}

x^2+y^2-2x-6y-15=0

x^{2} + y^{2} - 2 x - 6 y - 15 = 0

x^{2} = - 24 y

axis y=-x^2-6x-5 axis

y = - x^{2} - 6 x - 5

Frequently Asked Questions (FAQ)

What is the foci x=2y^2 ?
The foci x=2y^2 is (1/8 ,0)