What is x^2+y^2-14x+12y=36 ?

The solution to x^2+y^2-14x+12y=36 is Circle with (a,b)=(7,-6),r=11

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x^2+y^2-14x+12y=36

x^{2} + y^{2} - 14 x + 12 y = 36

(a, b) = (7, - 6), r = 11

Solution steps

x^{2} + y^{2} - 14 x + 12 y = 36

Rewrite

x^{2} + y^{2} - 14 x + 12 y = 36

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 6))^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (7, - 6), r = 11

x^{2} + y^{2} - 4 x - 6 y + 9 = 0

x^{2} + y^{2} = 144

2 (x - 3)^{2} + 2 y^{2} = 8

(x + 2)^{2} + (y - 1)^{2} = 4

(x - 1)^{2} + (y + 2)^{2} = 9

What is x^2+y^2-14x+12y=36 ?
The solution to x^2+y^2-14x+12y=36 is Circle with (a,b)=(7,-6),r=11