What is (x+2)^2+(y-1)^2=4 ?

The solution to (x+2)^2+(y-1)^2=4 is Circle with (a,b)=(-2,1),r=2

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(x+2)^2+(y-1)^2=4

(x + 2)^{2} + (y - 1)^{2} = 4

(a, b) = (- 2, 1), r = 2

Solution steps

(x + 2)^{2} + (y - 1)^{2} = 4

Rewrite

(x + 2)^{2} + (y - 1)^{2} = 4

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 2

(x - 1)^{2} + (y + 2)^{2} = 9

(x + 2)^{2} + (y - 1)^{2} = 25

9 x^{2} + 9 y^{2} + 42 x - 54 y + 49 = 0

(x - \frac{7}{4})^{2} + (y + \frac{3}{4})^{2} = \frac{169}{16}

(x - 2)^{2} + (y - 1)^{2} = 16

What is (x+2)^2+(y-1)^2=4 ?
The solution to (x+2)^2+(y-1)^2=4 is Circle with (a,b)=(-2,1),r=2