What is the axis f(x)=x^2-18x+80 ?

The axis f(x)=x^2-18x+80 is x=9

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axis f(x)=x^2-18x+80

axis

f (x) = x^{2} - 18 x + 80

x = 9

Solution steps

y = x^{2} - 18 x + 80

Rewrite

y = x^{2} - 18 x + 80

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 9

y = lo g_{5} (2) x^{2}

y = 25 x^{2} - 100

y = \frac{x ^{2} + x}{2}

y = 3 x^{2} - 8 x - 3

x = (3 y - 4) (4 y - 3) - 2 y