What is the axis y=3x^2-8x-3 ?

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axis y=3x^2-8x-3

axis

y = 3 x^{2} - 8 x - 3

x = \frac{4}{3}

Solution steps

y = 3 x^{2} - 8 x - 3

Rewrite

y = 3 x^{2} - 8 x - 3

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{25}{3})) = (x - \frac{4}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{4}{3}, - \frac{25}{3}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{4}{3}

x = (3 y - 4) (4 y - 3) - 2 y

y = - 2 x^{2} - 16 x - 25

y = 2 x^{2} - x - 1

y = 6 - 2 x^{2}

y = x^{2} - 24 x - 12