What is the axis y=x^2+100 ?

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axis y=x^2+100

axis

y = x^{2} + 100

x = 0

Solution steps

y = x^{2} + 100

Rewrite

y = x^{2} + 100

in the standard form:

4 \cdot \frac{1}{4} (y - 100) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 100), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x^{2} - 8 x + 14

f (x) = x^{2} - 18 x + 80

y = lo g_{5} (2) x^{2}

y = 25 x^{2} - 100

y = \frac{x ^{2} + x}{2}