What is the axis y=10-2x^2 ?

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axis y=10-2x^2

axis

y = 10 - 2 x^{2}

x = 0

Solution steps

y = 10 - 2 x^{2}

Rewrite

y = 10 - 2 x^{2}

in the standard form:

4 (- \frac{1}{8}) (y - 10) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 10), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = - 3 x^{2} + 10

y = 3 x^{2} - 10 x + 5

y = x^{2} - 8

y = \frac{1}{17} (x + 5)^{2}

y = x^{2} + 100