What is the axis (x+2)^2=-8y ?

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axis (x+2)^2=-8y

axis

(x + 2)^{2} = - 8 y

x = - 2

Solution steps

(x + 2)^{2} = - 8 y

Rewrite

(x + 2)^{2} = - 8 y

in the standard form:

4 (- 2) (y - 0) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 0), p = - 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

y = 10 - 2 x^{2}

y = - 3 x^{2} + 10

y = 3 x^{2} - 10 x + 5

y = x^{2} - 8

y = \frac{1}{17} (x + 5)^{2}