What is the axis y=-x^2+4x+3 ?

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axis y=-x^2+4x+3

axis

y = - x^{2} + 4 x + 3

x = 2

Solution steps

y = - x^{2} + 4 x + 3

Rewrite

y = - x^{2} + 4 x + 3

in the standard form

4 (- \frac{1}{4}) (y - 7) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 7), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = - 6 x^{2} + 4 x + 9

y = \frac{5 x ^{3} + 21 x ^{2} + 17 x - 3}{x + 3}

y = 2000 x - 5 x^{2}

y = - 2 (x - 3)^{2} + 2

y^{2} + 4 x = 0