What is the axis y=(5x^3+21x^2+17x-3)/(x+3) ?

The axis y=(5x^3+21x^2+17x-3)/(x+3) is x=-3/5

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axis y=(5x^3+21x^2+17x-3)/(x+3)

axis

x = - \frac{3}{5}

Solution steps

y = \frac{5 x ^{3} + 21 x ^{2} + 17 x - 3}{x + 3}

Rewrite

y = \frac{5 x ^{3} + 21 x ^{2} + 17 x - 3}{x + 3}

in the standard form

4 \cdot \frac{1}{20} (y - (- \frac{14}{5})) = (x - (- \frac{3}{5}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{5}, - \frac{14}{5}), p = \frac{1}{20}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{5}

What is the axis y=(5x^3+21x^2+17x-3)/(x+3) ?
The axis y=(5x^3+21x^2+17x-3)/(x+3) is x=-3/5