What is the axis x= 1/8 y^2 ?

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axis x= 1/8 y^2

axis

x = \frac{1}{8} y^{2}

y = 0

Solution steps

x = \frac{1}{8} y^{2}

Rewrite

x = \frac{1}{8} y^{2}

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 2

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = x^{2} + 19 x + 60

y = 2 x^{2} + 8 x - 24

- y^{2} + x - 4 = 0

x = - (y - 2)^{2} - 3

y = x^{2} - 2 x