What is the axis y=x^2+19x+60 ?

The axis y=x^2+19x+60 is x=-19/2

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axis y=x^2+19x+60

axis

y = x^{2} + 19 x + 60

x = - \frac{19}{2}

Solution steps

y = x^{2} + 19 x + 60

Rewrite

y = x^{2} + 19 x + 60

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{121}{4})) = (x - (- \frac{19}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{19}{2}, - \frac{121}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{19}{2}

y = 2 x^{2} + 8 x - 24

- y^{2} + x - 4 = 0

x = - (y - 2)^{2} - 3

y = x^{2} - 2 x

y = (x + 5) (x + 3)