What is the axis y=-13/11 (x+3)^2+1 ?

The axis y=-13/11 (x+3)^2+1 is x=-3

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axis y=-13/11 (x+3)^2+1

axis

y = - \frac{13}{11} (x + 3)^{2} + 1

x = - 3

Solution steps

y = - \frac{13}{11} (x + 3)^{2} + 1

Rewrite

y = - \frac{13}{11} (x + 3)^{2} + 1

in the standard form:

4 (- \frac{11}{52}) (y - 1) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 1), p = - \frac{11}{52}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y = (x - 3)^{2} - 2

y = \frac{x ^{2}}{6}

y^{2} - 6 y - 8 x + 17 = 0

y = (x + 2) (x - 2)

x - 3 + y^{2} = 2