What is the axis x-3+y^2=2 ?

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axis x-3+y^2=2

axis

x - 3 + y^{2} = 2

y = 0

Solution steps

x - 3 + y^{2} = 2

Rewrite

x - 3 + y^{2} = 2

in the standard form:

4 (- \frac{1}{4}) (x - 5) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (5, 0), p = - \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

(x + 5)^{2} = - 20 (y - 2)

y = (x + 1)^{2} + 5

y = (- x + 1)^{2} + 2

y = - 0.5 x^{2} - 3

y = 3 x^{2} + 5 x - 4